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Four equal resistance dissipated 5W of power together when connected in series to a battery of negligible internal resistance. The total power dissipated in these resistance when connected in parallel across the
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The power delivered by a battery of emf 10 V is 10 W then what is
SOLVED: For battery of voltage and internal resistance the total power delivered to load with resistance R is P = VR (R+r)2 Calculate assuming that is a variable and Ris constant. (Use
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If the terminals of a battery with zero internal resistance are connected across two identical resistors in series, the total power delivered by the battery is 8.00 W . If the same
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